document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133439>Question 133439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please find the unknown in the equation using steps <BR>\n" );
document.write( "log2 1056 = log2(2^a+5 plus 2^a) <BR>\n" );
document.write( "Please note that the 2 in the \"log2 1056\" is small: Please find the unknown in the equation using steps\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for answering the answer is correct:)\r<BR>\n" );
document.write( "\n" );
document.write( "but how do I answer this quesiton with logs appearing in at least one of the steps?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97633 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There have been a bunch of problems like this one recently. You might want to check the 'recently solved' before posting a problem that is already solved several times.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log2+1056+=+log2%282%5Ea%2B5+%2B+2%5Ea%29+ ALIGN=MIDDLE  ALT=\"log2+1056+=+log2%282%5Ea%2B5+%2B+2%5Ea%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "In tis problem, you can elininate the Log2 from both sides. You can just 'know that since a Log2 on the left is equal to the Log2 on the right, then the values are the same. Thus <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1056+=+2%5E%28a%2B5%29+%2B+2%5Ea ALIGN=MIDDLE  ALT=\"1056+=+2%5E%28a%2B5%29+%2B+2%5Ea\"   DISABLED_style= \"max-width:90%; height:auto;\" >. \r<BR>\n" );
document.write( "\n" );
document.write( "If you want to go a different way, take both sides of the equation and use the values there as exponents on the power of 2. So 2^(log2 1056) = 2^(2^a+5 + 2^a).<BR>\n" );
document.write( "That becomes 1056 Log2 2 = (2^(a+5) + 2^a) Log2 2. Since Log2 2 = 1, you get to the same equation as above.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1056+=+2%5E%28a%2B5%29+%2B+2%5Ea ALIGN=MIDDLE  ALT=\"1056+=+2%5E%28a%2B5%29+%2B+2%5Ea\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1056+=+2%5Ea+%2A+2%5E5+%2B+2%5Ea ALIGN=MIDDLE  ALT=\"1056+=+2%5Ea+%2A+2%5E5+%2B+2%5Ea\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+1056+=+32+%2A+2%5Ea+%2B+2%5Ea+ ALIGN=MIDDLE  ALT=\"+1056+=+32+%2A+2%5Ea+%2B+2%5Ea+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+1056+=+33+%2A+2%5Ea ALIGN=MIDDLE  ALT=\"+1056+=+33+%2A+2%5Ea\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+32+=+2%5E5 ALIGN=MIDDLE  ALT=\"+32+=+2%5E5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = 5\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );