document.write( "Question 133229: 204800=50*2^3/D \r
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Algebra.Com's Answer #97625 by scott8148(6628)\"\" \"About 
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dividing by 50 __ 4096=2^(3/D)\r
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\n" ); document.write( "\n" ); document.write( "2^12=2^(3/D) __ 12=3/D __ D=3/12\r
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\n" ); document.write( "\n" ); document.write( "note: 4096 is 4k in computer talk (binary) __ 1k=1024=2^10
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