document.write( "Question 133432: the length of a rectangle is 3 times the width, and the perimeter is 22. Find the deminsions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #97624 by jojo14344(1513)\"\" \"About 
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Given:
\n" ); document.write( "Width (W) = x (unknown)
\n" ); document.write( "Length (L) = 3 times the width = 3W = 3x
\n" ); document.write( "Perimeter (P) = 22
\n" ); document.write( "Formula:
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "Substitution,
\n" ); document.write( "22 = 2 ( 3W + W )
\n" ); document.write( "22 = 2 ( 3x + x)
\n" ); document.write( "22/2 = 4x
\n" ); document.write( "x= 2.75 ( width )
\n" ); document.write( "Therefor the length (L) = 3 W = 3 (2.75)
\n" ); document.write( " L = 8.25
\n" ); document.write( "To check:
\n" ); document.write( "P = 2 (L + W)
\n" ); document.write( "22= 2 (8.25 + 2.75)
\n" ); document.write( "22= 2 (11)
\n" ); document.write( "22= 22\r
\n" ); document.write( "\n" ); document.write( "Therefore, having Width = 2.75 is correct because it will arrived to a Perimeter of 22 as shown in th equation. Good Job! \n" ); document.write( "
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