document.write( "Question 133445This question is from textbook
\n" ); document.write( ": PLEASE HELP ME OUT.
\n" ); document.write( "A certain amount of 8% solution must be added to another amount of a 5% salt solution to produce a total of 36 ounces of a 6% solution. How many ounces of each solution is needed?
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Algebra.Com's Answer #97622 by josmiceli(19441)\"\" \"About 
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(total amount of salt) / (amount of solution) = 6%
\n" ); document.write( "Let \"a\"= amount of 8% solution to be added
\n" ); document.write( "Let \"b\"= amount of 5% solution to be added
\n" ); document.write( "\"%28.08a+%2B+.05b%29+%2F+%28a+%2B+b%29+=+.06\"
\n" ); document.write( "\"a+%2B+b+=+36\"
\n" ); document.write( "\"b+=+36+-+a\"
\n" ); document.write( "\"%28.08a+%2B+.05b%29+%2F+36+=+.06\"
\n" ); document.write( "\"%28.08a+%2B+.05%2836+-+a%29%29+%2F+36+=+.06\"
\n" ); document.write( "multiply both sides by \"36\"
\n" ); document.write( "\".08a+%2B+.05%2836+-+a%29+=+2.16\"
\n" ); document.write( "\".08a+%2B+1.8+-+.05a+=+2.16\"
\n" ); document.write( "\".03a+=+.36\"
\n" ); document.write( "\"a+=+12\"oz
\n" ); document.write( "\"b+=+36+-+a\"
\n" ); document.write( "\"b+=+36+-+12\"
\n" ); document.write( "\"b+=+24\"
\n" ); document.write( "12 oz of the 8% solution and 24 oz of the 5% solution are needed
\n" ); document.write( "check:
\n" ); document.write( "\"%28.08a+%2B+.05b%29+%2F+36+=+.06\"
\n" ); document.write( "\"%28.08%2A12+%2B+.05%2A24%29+%2F+36+=+.06\"
\n" ); document.write( "\"%28.96+%2B+1.2%29+%2F+36+=+.06\"
\n" ); document.write( "\".96+%2B+1.2+=+2.16\"
\n" ); document.write( "\"2.16+=+2.16\"
\n" ); document.write( "OK
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