document.write( "Question 133394: How can 28,0000 be invested, part at 4% annual simple interest and the remainder at 10%, so that the interest earned by the two accounts is equal at the end of the year? \n" ); document.write( "
Algebra.Com's Answer #97582 by stanbon(75887) ![]() You can put this solution on YOUR website! How can 28,0000 be invested, part at 4% annual simple interest and the remainder at 10%, so that the interest earned by the two accounts is equal at the end of the year? \n" ); document.write( "-------------------------- \n" ); document.write( "Let amt. invested at 4% be \"x\"; Interest is 0.04x dollars \n" ); document.write( "--------------------------- \n" ); document.write( "Amt invsted at 10% is \"28000-x\" ; Interest is 0.1(28000-x)=2800-0.1x \n" ); document.write( "---------------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "interest = interest \n" ); document.write( "0.04x = 2800-0.10x \n" ); document.write( "0.14x = 2800 \n" ); document.write( "x = $20000 (amount invested at 4%) \n" ); document.write( "------------ \n" ); document.write( "28000-x = $8000 (amount invested at 10%) \n" ); document.write( "============================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |