document.write( "Question 133394: How can 28,0000 be invested, part at 4% annual simple interest and the remainder at 10%, so that the interest earned by the two accounts is equal at the end of the year? \n" ); document.write( "
Algebra.Com's Answer #97582 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How can 28,0000 be invested, part at 4% annual simple interest and the remainder at 10%, so that the interest earned by the two accounts is equal at the end of the year?
\n" ); document.write( "--------------------------
\n" ); document.write( "Let amt. invested at 4% be \"x\"; Interest is 0.04x dollars
\n" ); document.write( "---------------------------
\n" ); document.write( "Amt invsted at 10% is \"28000-x\" ; Interest is 0.1(28000-x)=2800-0.1x
\n" ); document.write( "----------------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "interest = interest
\n" ); document.write( "0.04x = 2800-0.10x
\n" ); document.write( "0.14x = 2800
\n" ); document.write( "x = $20000 (amount invested at 4%)
\n" ); document.write( "------------
\n" ); document.write( "28000-x = $8000 (amount invested at 10%)
\n" ); document.write( "=============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );