document.write( "Question 133399: Could someone please help me with this problem. I need to find the equation of the line parallel to 2y = -x + 3 which passes through (0,4)\r
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document.write( "My solution was to simplify 2y = -x + 3
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document.write( "So I tried 2y/2 = -x/2 + 3/2
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document.write( "so I came up with y = -x/2 + 3/2 but I am yucky with fractions. Could someone tell me if I am on the right page or not? \n" );
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Algebra.Com's Answer #97581 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! find the equation of the line parallel to 2y = -x + 3 which passes through (0,4) \n" ); document.write( "------------------------- \n" ); document.write( "The given equation has a slope: \n" ); document.write( "y = (-1/2)x + (3/2) \n" ); document.write( "slope = -1/2 \n" ); document.write( "------------------------------- \n" ); document.write( "Any line parallel to it must have slope = -1/2 \n" ); document.write( "------------------------------ \n" ); document.write( "Form of the line is y = mx+b \n" ); document.write( "You have y,x, and m; solve for b. \n" ); document.write( "4 = (-1/2)*0 + b \n" ); document.write( "b = 4 \n" ); document.write( "-------------- \n" ); document.write( "EQUATION: \n" ); document.write( "y = (-1/2)x + 4 \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |