document.write( "Question 133399: Could someone please help me with this problem. I need to find the equation of the line parallel to 2y = -x + 3 which passes through (0,4)\r
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\n" ); document.write( "\n" ); document.write( "My solution was to simplify 2y = -x + 3
\n" ); document.write( "So I tried 2y/2 = -x/2 + 3/2
\n" ); document.write( "so I came up with y = -x/2 + 3/2 but I am yucky with fractions. Could someone tell me if I am on the right page or not?
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Algebra.Com's Answer #97581 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
find the equation of the line parallel to 2y = -x + 3 which passes through (0,4)
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\n" ); document.write( "The given equation has a slope:
\n" ); document.write( "y = (-1/2)x + (3/2)
\n" ); document.write( "slope = -1/2
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\n" ); document.write( "Any line parallel to it must have slope = -1/2
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\n" ); document.write( "Form of the line is y = mx+b
\n" ); document.write( "You have y,x, and m; solve for b.
\n" ); document.write( "4 = (-1/2)*0 + b
\n" ); document.write( "b = 4
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\n" ); document.write( "EQUATION:
\n" ); document.write( "y = (-1/2)x + 4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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