document.write( "Question 133376: Bob's friend Tim is 4 times as old as he is. Six years from now, Tim will be twice as old as Bob will be. How old is Bob now? Algebra 1. \n" ); document.write( "
Algebra.Com's Answer #97562 by oscargut(2103)\"\" \"About 
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Let Bob's age = x
\n" ); document.write( "And Tim's age = y
\n" ); document.write( "then y=4x because (Tim is 4 times as old as Bob is)
\n" ); document.write( "y+6=2(x+6)(Six years from now, Tim will be twice as old as Bob will be)
\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "4x+6=2x+12
\n" ); document.write( "then
\n" ); document.write( "2x=6
\n" ); document.write( "x=3
\n" ); document.write( "and y = 12
\n" ); document.write( "Answer: Bob is 3 years now
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