document.write( "Question 133354: Randolf bought a high-end computer system for $4800. The system depreciates at the rate of 25% each year.\r
\n" ); document.write( "\n" ); document.write( "Determine an exponential funciton to model the value of the system over time. YOu might use a table of values with columns for years, the expression for calculation for that year, and the value on that year to help you in your derivation.\r
\n" ); document.write( "\n" ); document.write( "I understand how to get the exponential funciton but I am having difficulty with the table, expression and value.\r
\n" ); document.write( "\n" ); document.write( "I would appreciate if anyone can help me,\r
\n" ); document.write( "\n" ); document.write( "your friend,\r
\n" ); document.write( "\n" ); document.write( "Johnathan \n" ); document.write( "

Algebra.Com's Answer #97552 by checkley71(8403) $\"\"$ $\"About$

You can put this solution on YOUR website!
4800*.25=1200 IS THE ANNUAL DEPRECIATION.
\n" ); document.write( "FIRST YEAR AFTER PURCHASE - 4800-1200=3600
\n" ); document.write( "SECOND YEAR 3600-1200=2400
\n" ); document.write( "THIRD YEAR 2400-1200=1200
\n" ); document.write( "FOURTH YEAR 1200-1200=0 NO VALUE LEFT.
\n" ); document.write( "OR IF IT IS 25% OF THE REMAING VALUE THEN WE HAVE:
\n" ); document.write( "4800*.75=3600 @ THE END OF YEAR 1
\n" ); document.write( "3600*.75=2700 @ THE END OF YEAR 2
\n" ); document.write( "2700*.75=2025 @ THE END OF YEAR 3
\n" ); document.write( "2025*.75=1518.75 @ THE END OF YEAR 4
\n" ); document.write( "1518.75*.75=1139.O6 @ THE END OF YEAR 5.
\n" ); document.write( "1139.06*.75=854.30 @ THE END OF YEAR 6 ETC. \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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