document.write( "Question 133368: I used the problem provided to try to get the answer. I would like to know if this is correct using the synthetic division method.\r
\n" ); document.write( "\n" ); document.write( "(5x^2+34y+24)/ (y-2)\r
\n" ); document.write( "\n" ); document.write( "2 5 34 24
\n" ); document.write( " 10 88
\n" ); document.write( " 5 44 112 5y+44y+24 112/y+2
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Algebra.Com's Answer #97551 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
This expression MUST have one variable if you want to use a simple form of synthetic division here. So I'm assuming that the expression is \r
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\n" ); document.write( "\n" ); document.write( "\"%285%2Ax%5E2%2B34%2Ax%2B24%29%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let's simplify this expression using synthetic division\r
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\n" ); document.write( "\n" ); document.write( "Start with the given expression \"%285x%5E2+%2B+34x+%2B+24%29%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "First lets find our test zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0\" Set the denominator \"x-2\" equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Solve for x.\r
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\n" ); document.write( "\n" ); document.write( "so our test zero is 2\r
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\n" ); document.write( "\n" ); document.write( "Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.\n" ); document.write( "\n" ); document.write( "
2|53424
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\r
\n" ); document.write( "\n" ); document.write( "Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 5)\r
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2|53424
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5
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\n" ); document.write( "\n" ); document.write( " Multiply 2 by 5 and place the product (which is 10) right underneath the second coefficient (which is 34)\r
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2|53424
|10
5
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\n" ); document.write( "\n" ); document.write( " Add 10 and 34 to get 44. Place the sum right underneath 10.\r
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2|53424
|10
544
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\n" ); document.write( "\n" ); document.write( " Multiply 2 by 44 and place the product (which is 88) right underneath the third coefficient (which is 24)\r
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2|53424
|1088
544
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\n" ); document.write( "\n" ); document.write( " Add 88 and 24 to get 112. Place the sum right underneath 88.\r
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2|53424
|1088
544112
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\n" ); document.write( "\n" ); document.write( "Since the last column adds to 112, we have a remainder of 112. This means \"x-2\" is not a factor of \"5x%5E2+%2B+34x+%2B+24\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the bottom row of coefficients:\r
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\n" ); document.write( "\n" ); document.write( "The first 2 coefficients (5,44) form the quotient\r
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\n" ); document.write( "\n" ); document.write( "\"5x+%2B+44\"\r
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\n" ); document.write( "\n" ); document.write( "and the last coefficient 112, is the remainder, which is placed over \"x-2\" like this\r
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\n" ); document.write( "\n" ); document.write( "\"112%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Putting this altogether, we get:\r
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\n" ); document.write( "\n" ); document.write( "\"5x+%2B+44%2B112%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%285x%5E2+%2B+34x+%2B+24%29%2F%28x-2%29=5x+%2B+44%2B112%2F%28x-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "which looks like this in remainder form:\r
\n" ); document.write( "\n" ); document.write( "\"%285x%5E2+%2B+34x+%2B+24%29%2F%28x-2%29=5x+%2B+44\" remainder 112\r
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\n" ); document.write( "\n" ); document.write( "You can use this online polynomial division calculator to check your work\r
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