document.write( "Question 133352: 64x^3+343\r
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\n" ); document.write( "\n" ); document.write( "these are the two polynomials im left with!
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Algebra.Com's Answer #97539 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Do you want to factor?\r
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\n" ); document.write( "\n" ); document.write( "\"64x%5E3%2B343\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%29%5E3%2B%287%29%5E3\" Rewrite \"64x%5E3\" as \"%284x%29%5E3\". Rewrite \"343\" as \"%287%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B7%29%28%284x%29%5E2-%284x%29%287%29%2B%287%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B7%29%2816x%5E2-28x%2B49%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"64x%5E3%2B343\" factors to \"%284x%2B7%29%2816x%5E2-28x%2B49%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"64x%5E3%2B343=%284x%2B7%29%2816x%5E2-28x%2B49%29\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"1x%5E4%2B8x%5E2-9\" we can see that the first term is \"1x%5E4\" and the last term is \"-9\" where the coefficients are 1 and -9 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient -9 to get -9. Now what two numbers multiply to -9 and add to the middle coefficient 8? Let's list all of the factors of -9:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -9:\r
\n" ); document.write( "\n" ); document.write( "1,3\r
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\n" ); document.write( "\n" ); document.write( "-1,-3 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -9\r
\n" ); document.write( "\n" ); document.write( "(1)*(-9)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(9)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 8? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 8\r
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First NumberSecond NumberSum
1-91+(-9)=-8
-19-1+9=8
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and 9 add up to 8 and multiply to -9\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1x%5E4%2B8x%5E2-9\", replace \"8x%5E2\" with \"-1x%5E2%2B9x%5E2\" (notice \"-1x%5E2%2B9x%5E2\" adds up to \"8x%5E2\". So it is equivalent to \"8x%5E2\")\r
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\n" ); document.write( "\n" ); document.write( "\"1x%5E4%2Bhighlight%28-1x%5E2%2B9x%5E2%29%2B-9\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1x%5E4-1x%5E2%2B9x%5E2-9\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%5E4-1x%5E2%29%2B%289x%5E2-9%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%5E2-1%29%2B9%28x%5E2-1%29\" Factor out the GCF of \"x%5E2\" out of the first group. Factor out the GCF of \"9\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B9%29%28x%5E2-1%29\" Since we have a common term of \"x%5E2-1\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1x%5E4-1x%5E2%2B9x%5E2-9\" factors to \"%28x%5E2%2B9%29%28x%5E2-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1x%5E4%2B8x%5E2-9\" factors to \"%28x%5E2%2B9%29%28x%5E2-1%29\" (since \"1x%5E4%2B8x%5E2-9\" is equivalent to \"1x%5E4-1x%5E2%2B9x%5E2-9\")\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E4%2B8x%5E2-9\" factors to \"%28x%5E2%2B9%29%28x%5E2-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B9%29%28x%2B1%29%28x-1%29\" Now factor \"x%5E2-1\" by using the difference of squares\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E4%2B8x%5E2-9\" factors to \"%28x%5E2%2B9%29%28x%2B1%29%28x-1%29\"
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