document.write( "Question 133279: Please solve with steps \r
\n" ); document.write( "\n" ); document.write( "27(3^3x+1) = 3
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Algebra.Com's Answer #97527 by josmiceli(19441)\"\" \"About 
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\"27%2A%283%5E%283x%2B1%29%29+=+3\"
\n" ); document.write( "\"3%5E%283x%2B1%29+=+1%2F9\"
\n" ); document.write( "\"3%5E%283x%2B1%29+=+1%2F%283%5E2%29\"
\n" ); document.write( "\"3%5E%283x%2B1%29+=+3%5E%28-2%29\"
\n" ); document.write( "\"3x+%2B+1+=+-2\"
\n" ); document.write( "\"3x+=+-3\"
\n" ); document.write( "\"x+=+-1\" answer
\n" ); document.write( "check answer:
\n" ); document.write( "\"27%2A%283%5E%283x%2B1%29%29+=+3\"
\n" ); document.write( "\"27%2A%283%5E%283%2A%28-1%29%2B1%29%29+=+3\"
\n" ); document.write( "\"27%2A%283%5E%28-2%29%29+=+3\"
\n" ); document.write( "\"27+%2F+%283%5E2%29+=+3\"
\n" ); document.write( "\"27%2F9+=+3\"
\n" ); document.write( "\"3+=+3\"
\n" ); document.write( "OK
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