document.write( "Question 133332: logx + log(x + 3) = 1\r
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Algebra.Com's Answer #97522 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%2810%2C%28x%29%29%2Blog%2810%2C%28x%2B3%29%29=1\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%28x%2B3%29%29%29=1\" Combine the logs using the identity \"log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28x%5E2%2B3x%29%29=1\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"10%5E%28log%2810%2C%28x%5E2%2B3x%29%29%29=10%5E1\" Raise both sides as exponents with bases of 10. This eliminates the logs\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x=10\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x-10=0\" Subtract 10 from both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%28x-2%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5=0\" or \"x-2=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=-5\" or \"x=2\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our possible answers are \r
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\n" ); document.write( "\n" ); document.write( " \"x=-5\" or \"x=2\" \r
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\n" ); document.write( "\n" ); document.write( "However, since you cannot take the log of a negative number, the only solution is \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"x=2\"
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