document.write( "Question 133324: Rewrite the expression x^3 - 2x^2 y + x y^2 so that it is easy to calculate the its value without a calculator when x= 21 and y = 19 \n" ); document.write( "
Algebra.Com's Answer #97518 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-2x%5E2y%2B1xy%5E2\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2-2xy%2By%5E2%29\" Factor out the GCF \"x\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"x%5E2-2xy%2By%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"1x%5E2-2xy%2B1y%5E2\" we can see that the first term is \"1x%5E2\" and the last term is \"1y%5E2\" where the coefficients are 1 and 1 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient -2? Let's list all of the factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "Factors of 1:\r
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\n" ); document.write( "\n" ); document.write( "-1 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to 1\r
\n" ); document.write( "\n" ); document.write( "1*1\r
\n" ); document.write( "\n" ); document.write( "(-1)*(-1)\r
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\n" ); document.write( "\n" ); document.write( "note: remember two negative numbers multiplied together make a positive number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to -2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -2\r
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First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -1 and -1 add up to -2 and multiply to 1\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"1x%5E2-2xy%2B1y%5E2\", replace \"-2xy\" with \"-1xy%2B-1xy\" (notice \"-1xy%2B-1xy\" adds up to \"-2xy\". So it is equivalent to \"-2xy\")\r
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\n" ); document.write( "\n" ); document.write( "\"1x%5E2%2Bhighlight%28-1xy%2B-1xy%29%2B1y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"1x%5E2-1xy-1xy%2B1y%5E2\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%5E2-1xy%29%2B%28-1xy%2B1y%5E2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-y%29-y%28x-y%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"-y\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-y%29%28x-y%29\" Since we have a common term of \"x-y\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"1x%5E2-1xy-1xy%2B1y%5E2\" factors to \"%28x-y%29%28x-y%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"1x%5E2-2xy%2B1y%5E2\" factors to \"%28x-y%29%28x-y%29\" (since \"1x%5E2-2xy%2B1y%5E2\" is equivalent to \"1x%5E2-1xy-1xy%2B1y%5E2\")\r
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\n" ); document.write( "\n" ); document.write( "note: \"%28x-y%29%28x-y%29\" is equivalent to \"%28x-y%29%5E2\" since the term \"x-y\" occurs twice. So \"1x%5E2-2xy%2B1y%5E2\" also factors to \"%28x-y%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"x%28x%5E2-2xy%2By%5E2%29\" and factors further to \"x%28x-y%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3-2x%5E2y%2Bxy%5E2\" factors to \"x%28x-y%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"21%2821-19%29%5E2\" Plug in x= 21 and y = 19 \r
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\n" ); document.write( "\n" ); document.write( "\"21%282%29%5E2\" Subtract \r
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\n" ); document.write( "\n" ); document.write( "\"21%284%29\" Square 2 to get 4\r
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\n" ); document.write( "\n" ); document.write( "\"84\" Multiply \r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3+-+2x%5E2+y+%2B+x+y%5E2=84\" when x= 21 and y = 19
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