document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133316>Question 133316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use logs ( any base) to find the unknown:\r<BR>\n" );
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document.write( "3 to the power of x^2 minus 2x = 3 to the power of x-2 ( there are two answers please find both) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97502 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 to the power of x^2 minus 2x = 3 to the power of x-2 <BR>\n" );
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document.write( "3^(x^2-2x) = 3^(x-2)<BR>\n" );
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document.write( "Take the log(base3) of both sides to get:<BR>\n" );
document.write( "x^2-2x = x-2<BR>\n" );
document.write( "x^2-3x+2 = 0<BR>\n" );
document.write( "(x-2)(x-1) = 0<BR>\n" );
document.write( "x = 2 or x=1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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