document.write( "Question 133315: This questions gives me the jitters...\r
\n" ); document.write( "\n" ); document.write( "Solve using logs:2^2x+4 minus 2^2x =120\r
\n" ); document.write( "\n" ); document.write( "I know the answer but not the steps:(
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Algebra.Com's Answer #97501 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve using logs:2^(2x+4) - 2^2x =120
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\n" ); document.write( "Since 2^(a+b) = 2^a*2^b you get:\r
\n" ); document.write( "\n" ); document.write( "2^2x*2^4 -2^2x = 120
\n" ); document.write( "But 2^4 = 16\r
\n" ); document.write( "\n" ); document.write( "16(2^2x) - 2^2x - 120\r
\n" ); document.write( "\n" ); document.write( "But 16a - a = 15a.
\n" ); document.write( "So you have:
\n" ); document.write( "15*2^2x = 120
\n" ); document.write( "Divide both sides by 15 to get:
\n" ); document.write( "2^2x = 120/15
\n" ); document.write( "2^2x = 80
\n" ); document.write( "2x log2 = log80
\n" ); document.write( "2x = log80/log2
\n" ); document.write( "2x = 6.321928..
\n" ); document.write( "x = 3.160964...
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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