document.write( "Question 133315: This questions gives me the jitters...\r
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document.write( "Solve using logs:2^2x+4 minus 2^2x =120\r
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document.write( "I know the answer but not the steps:( \n" );
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Algebra.Com's Answer #97501 by stanbon(75887) ![]() You can put this solution on YOUR website! Solve using logs:2^(2x+4) - 2^2x =120 \n" ); document.write( "---------------- \n" ); document.write( "Since 2^(a+b) = 2^a*2^b you get:\r \n" ); document.write( "\n" ); document.write( "2^2x*2^4 -2^2x = 120 \n" ); document.write( "But 2^4 = 16\r \n" ); document.write( "\n" ); document.write( "16(2^2x) - 2^2x - 120\r \n" ); document.write( "\n" ); document.write( "But 16a - a = 15a. \n" ); document.write( "So you have: \n" ); document.write( "15*2^2x = 120 \n" ); document.write( "Divide both sides by 15 to get: \n" ); document.write( "2^2x = 120/15 \n" ); document.write( "2^2x = 80 \n" ); document.write( "2x log2 = log80 \n" ); document.write( "2x = log80/log2 \n" ); document.write( "2x = 6.321928.. \n" ); document.write( "x = 3.160964... \n" ); document.write( "----------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |