document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133252>Question 133252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the unknown in the equation log2 48 = log2(2^x+2 minus 2^x)\r<BR>\n" );
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document.write( "Please show me the steps to get to the answer, which is x = 4\r<BR>\n" );
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document.write( "Stanbon,, you are the man </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97458 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log2 48 = log2(2^(x+2) - 2^x) \r<BR>\n" );
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document.write( "log2 48 = log2(2^2*2^x - 2^x)\r<BR>\n" );
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document.write( "log2 48 = log2(2^x(4-1))\r<BR>\n" );
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document.write( "log2 48 = log2(3*2^x)\r<BR>\n" );
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document.write( "log2 48 = log2 3 + log2 2^x\r<BR>\n" );
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document.write( "log2 48 = log2 3 + x\r<BR>\n" );
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document.write( "x = log2 48 - log2 3\r<BR>\n" );
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document.write( "x = log2 (48/3)\r<BR>\n" );
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document.write( "x = log2 16\r<BR>\n" );
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document.write( "x = 4<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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