document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20170>Question 20170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-y=2<BR>\n" );
document.write( "4x-3y=11<BR>\n" );
document.write( "How do I solve the sytem of equation using the subsitution method?  Please show the work! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9741 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to find x or y in one of the equations and then substitute that into the other.<BR>\n" );
document.write( "So we have;<BR>\n" );
document.write( "x-y=2<BR>\n" );
document.write( "4x-3y=11<BR>\n" );
document.write( "We will take the first equation and find x;<BR>\n" );
document.write( "x-y=2<BR>\n" );
document.write( "add y to both sides;<BR>\n" );
document.write( "x-y+y=2+y<BR>\n" );
document.write( "x=2+y<BR>\n" );
document.write( "Now we ttake that answer and substitute it forx in the other equation;<BR>\n" );
document.write( "4(2+y)-3y=11<BR>\n" );
document.write( "8+4y-3y=11<BR>\n" );
document.write( "8+y=11<BR>\n" );
document.write( "y=3<BR>\n" );
document.write( "Now we have what y equals, so we use it in the first equation to find x;<BR>\n" );
document.write( "x-3=2<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "So we have;<BR>\n" );
document.write( "x=5; y=3<BR>\n" );
document.write( "Hope you understand!<BR>\n" );
document.write( "=) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );