document.write( "Question 133198This question is from textbook prentice hall mathematics algebra 2
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document.write( ": Please help me solve this prroblem:
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document.write( "A passenger train travels 392mi in the same time that it takes a freight train to travel 322mi. if the passenger train travels 20mi/h faster than the freight train, find the speed of each train \n" );
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Algebra.Com's Answer #97404 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let r=rate of freight train \n" ); document.write( "Then r+20=rate of passenger train\r \n" ); document.write( "\n" ); document.write( "Time it takes freight train=322/r \n" ); document.write( "Time it takes passenger train=392/(r+20)\r \n" ); document.write( "\n" ); document.write( "Now we are told that the above two times are equal, so:\r \n" ); document.write( "\n" ); document.write( "322/r=392/(r+20) multiply each side by r(r+20) (or cross multiply)\r \n" ); document.write( "\n" ); document.write( "322(r+20)=392r get rid of parens\r \n" ); document.write( "\n" ); document.write( "322r+6440=392r subtract 322r from each side\r \n" ); document.write( "\n" ); document.write( "322r-322r+6440=392r-322r collect like terms \n" ); document.write( "6440=70r divide both sides by 70\r \n" ); document.write( "\n" ); document.write( "r=92 mph------------------------------speed of freight train\r \n" ); document.write( "\n" ); document.write( "r+20=92+20=112 mph------------------------speed of passenger train\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "322/92=392/112 \n" ); document.write( "3.5=3.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |