document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133131>Question 133131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The weekly revenue for a company is R = -3p^2+60p+1060, where p is the price of the company's product.  Find the maximum revenue for this company.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for your help.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97372 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The weekly revenue for a company is R = -3p^2+60p+1060, where p is the price of the company's product.  Find the maximum revenue for this company.<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "max occurs at p = -b/2a = -60/(2*-3) = 10<BR>\n" );
document.write( "Revenue when = 10 is R(10) = -3*100+60*10+1060<BR>\n" );
document.write( "= $1360<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );