document.write( "Question 133123: A piece of copper tubing 60 inches long is cut into two unequal pieces. Each piece is formed into a square frame. If the total area of the two frames are 117 square inches, what is the length of each piece of tubing?\r
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Algebra.Com's Answer #97362 by vleith(2983)\"\" \"About 
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Given: 60 inches of pipe. cut into to pieces. Formed into 2 squares with a total area of 117 sq inches.\r
\n" ); document.write( "\n" ); document.write( "Let the first piece be A. Then the second piece = (60-A)\r
\n" ); document.write( "\n" ); document.write( "To form a square with perimeter of A, each side must be A/4. So the area of that square is \"A%5E2%2F16\"\r
\n" ); document.write( "\n" ); document.write( "Likewise, the area of the other frame is \"%28%2860-A%29%2F4%29%5E2\"
\n" ); document.write( "or \"%283600+-120A+%2BA%5E2%29%2F16\"\r
\n" ); document.write( "\n" ); document.write( "The sum of the two areas is 117
\n" ); document.write( "So
\n" ); document.write( "\"117+=+%28A%5E2%2F16%29+%2B+%283600+-120A+%2BA%5E2%29%2F16\"
\n" ); document.write( "\"0+=+A%5E2+-60A+%2B+864\" factor or use quadratic equation
\n" ); document.write( "\"+0+=+%28A+-24%29%28A+-+36%29\"
\n" ); document.write( "So A is 24 and the other piece is 36.
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