document.write( "Question 133125: A rectangle is 6 cm long and 5 cm wide. When each dimension is increased by x cm, the total area is tripled. Find the value of x using algebra.\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help. \n" ); document.write( "
Algebra.Com's Answer #97344 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
A rectangle is 6 cm long and 5 cm wide. When each dimension is increased by x cm, the total area is tripled. Find the value of x using algebra.
\n" ); document.write( "total area =6*5=30 then
\n" ); document.write( "(6+x)(5+x)=3(30)
\n" ); document.write( "then x^2+11x+30=90
\n" ); document.write( "then x^2+11x+-60=0
\n" ); document.write( "then x=(-11+sqrt(361))/2 = 4
\n" ); document.write( "or x=(-11-sqrt(361))/2 =-15
\n" ); document.write( "x is >0
\n" ); document.write( "then x= 4 \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );