document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=133078>Question 133078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a population of intial size 100 grows at the rate of 8% per year forever.  What is the size of the population at the end of year n (for any integer n)?  What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97311 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the population in any year would be<BR>\n" );
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document.write( "So to solve for a population of 200<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=200+=+100+%281.08%29%5En+ ALIGN=MIDDLE  ALT=\"200+=+100+%281.08%29%5En+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2+=+%281.08%29%5En+ ALIGN=MIDDLE  ALT=\"2+=+%281.08%29%5En+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Plug in a few numbers and you'll find that about 9 years will double the population (that is a handy thing to know when calculating interest too. Remember the 'rule of 72'. Divide 72 by the interest rate (in this case 8) and see that is will take about 9 years to double. </SPAN>\n" );
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