document.write( "Question 133076: Michael rows 8 mph in still water. If he rows 24 miles downstream in the same amount of time he rows 8 miles upstream, find the rate of the current.\r
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Algebra.Com's Answer #97292 by solver91311(24713)\"\" \"About 
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rate of the current: r
\n" ); document.write( "downstream rate of the boat: 8 + r
\n" ); document.write( "upstream rate of the boat: 8 - r\r
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\n" ); document.write( "\n" ); document.write( "distance = rate times time, or \"d=rt\", so \"t=d%2Fr\".\r
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\n" ); document.write( "\n" ); document.write( "Downstream trip: \"t=24%2F%288%2Br%29\"
\n" ); document.write( "Upstream trip: \"t=8%2F%288-r%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since the times for each trip are equal:\r
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\n" ); document.write( "\n" ); document.write( "\"8%2F%288-r%29=24%2F%288%2Br%29\"\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply:
\n" ); document.write( "\"8%288%2Br%29=24%288-r%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute:
\n" ); document.write( "\"64%2B8r=192-24r\"\r
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\n" ); document.write( "\n" ); document.write( "Collect like terms:
\n" ); document.write( "\"8r%2B24r=192-64\"\r
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\n" ); document.write( "\n" ); document.write( "\"32r=128\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=4\"\r
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\n" ); document.write( "\n" ); document.write( "So the rate of the current is 4.\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "8mph + 4mph = 12mph, 24m/12mph = 2 hr\r
\n" ); document.write( "\n" ); document.write( "8mph - 4mph = 4mph, 8m/4mph = 2 hr\r
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