document.write( "Question 20148: Please help!\r
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document.write( "One painter works 1 1/2 times as fast as another. Find their individual rates for painting a room if together it takes them 4 hours. \n" );
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Algebra.Com's Answer #9726 by suresh(20) ![]() You can put this solution on YOUR website! Let x be the working rate of first painter and y be the rate of second painter.\r \n" ); document.write( "\n" ); document.write( "Given: \n" ); document.write( "x = (3/2) y\r \n" ); document.write( "\n" ); document.write( "If they together work,they will complete the work in 4 hours.\r \n" ); document.write( "\n" ); document.write( "For one hour first painter works 1/x and second painter 1/y\r \n" ); document.write( "\n" ); document.write( "i.e. 1/x + 1/y = 1/4\r \n" ); document.write( "\n" ); document.write( " 2/3y+1/y=1/4 \n" ); document.write( " \n" ); document.write( " 5/3y = 1/4\r \n" ); document.write( "\n" ); document.write( " 1/y=3/20\r \n" ); document.write( "\n" ); document.write( "For second painter can do the work at the rate 20/3.\r \n" ); document.write( "\n" ); document.write( "For first painter can do the work at the rate (3/2)*(20/3)=10 \n" ); document.write( " |