document.write( "Question 132854: A rectangle has an area of 36 square meters. Its length is 2square-root of 3 meters. In exact form, what is the permieter of the rectangle?
\n" ); document.write( "A right triangle has a 24-cm perimeter, and its hypotenuse is twice as long as its shoter leg. To the nearest tenth of a cm, fnd the lengths of all three sides of this triangle.
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Algebra.Com's Answer #97251 by nycsharkman(136)\"\" \"About 
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You have two questions here.\r
\n" ); document.write( "\n" ); document.write( "Question(1).
\n" ); document.write( "for the long side of the rectangle is x,
\n" ); document.write( "the short side of the rectangle is y,
\n" ); document.write( "x*y=36m^2
\n" ); document.write( "x=2sqrt3 y=36/2sqrt3=6sqrt3
\n" ); document.write( "perimeter=2(x+y)=2(2sqrt3+6sqrt3)=16sq...\r
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\n" ); document.write( "\n" ); document.write( "Question (2)
\n" ); document.write( "short leg of triangle=a
\n" ); document.write( "long leg of triangle=b
\n" ); document.write( "hypotenus=h=2a
\n" ); document.write( "h^2=a^2+b^2
\n" ); document.write( "b^2=3a^2
\n" ); document.write( "b=asqrt3
\n" ); document.write( "h+a+b=3a+b=24
\n" ); document.write( "3a+asqrt3=24, a(3+sqrt3)=24, a=24/(3+sqrt3)
\n" ); document.write( "if we multiply the denominator with (3-3sqrt3)
\n" ); document.write( "then a=(12-4sqrt3)
\n" ); document.write( "b=sqrt3*a=sqrt3*(12-4sqrt3)=12sqrt3-12
\n" ); document.write( "h=2a=24-8sqrt3
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