document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=20150>Question 20150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this problem using the pythagrean theorum. One leg of a right triangle is 8 inches long.  The hypotenuse is 2 inches longer than the other leg.  What is the length of the hypotenuse. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9724 by </B><A HREF=/tutors/aboutme.mpl?userid=suresh><B>suresh(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=suresh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By pythagrean theorem,\r<BR>\n" );
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document.write( "(hupotenuse)^2 = sum of squares of the legs\r<BR>\n" );
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document.write( "Given<BR>\n" );
document.write( "leg1=8<BR>\n" );
document.write( "We have to find leg2.<BR>\n" );
document.write( "Let x be the length of leg2.<BR>\n" );
document.write( "Given that hypotenuse(h) is 2 inches longer then x.<BR>\n" );
document.write( "So h=x+2\r<BR>\n" );
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document.write( "therefore,h^2=8^2+x^2<BR>\n" );
document.write( "(x+2)^2=64+x^2<BR>\n" );
document.write( "x^2+4x+4=64+x^2<BR>\n" );
document.write( "4x+4=64  (cancellation law)<BR>\n" );
document.write( "4x=60<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "Hence the length of other side is 15 inches </SPAN>\n" );
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