document.write( "Question 132924: A spice mixture is 25% thyme. How many grams of thyme must be added to 12 g. of the misture to increase the thyme content to 40%? \n" ); document.write( "

Algebra.Com's Answer #97238 by nycsharkman(136) $\"\"$ $\"About$

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A spice mixture is 25% thyme. How many grams of thyme must be added to 12 grams of the mixture to increase the thyme content to 40%?\r
\n" ); document.write( "\n" ); document.write( "Let x = amount of grams of thyme that must be added\r
\n" ); document.write( "\n" ); document.write( "Let's pretend that we have three cups.\r
\n" ); document.write( "\n" ); document.write( "In the cup 1, we have 12 grams times 25%.\r
\n" ); document.write( "\n" ); document.write( "In cup 2, we have x grams.\r
\n" ); document.write( "\n" ); document.write( "In cup 3, we have (0.40)(x + 12) grams.\r
\n" ); document.write( "\n" ); document.write( "We now have this equation:\r
\n" ); document.write( "\n" ); document.write( "12(0.25) + x = 0.40x + 4.80\r
\n" ); document.write( "\n" ); document.write( "3 + x = .40x + 4.80\r
\n" ); document.write( "\n" ); document.write( "x - .40x = 4.80 - 3\r
\n" ); document.write( "\n" ); document.write( ".60x = 1.80\r
\n" ); document.write( "\n" ); document.write( "x = 1.80/.60\r
\n" ); document.write( "\n" ); document.write( "x = 3 grams MUST BE ADDED \n" ); document.write( "

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