document.write( "Question 20107: Solve the following problem. \r
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document.write( "Ace manufacturing has determined that the cost of labor for producing transmissions is 0.3x^2+400x+550 dollars, while the cost of materials is 0.1x^2+50x+800 dollars.\r
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document.write( "a. Write a polynomial that represents the total cost of materials and labor for producing x transmissions.
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document.write( "b. Evaluate the total cost polynomial for x=500.
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document.write( "c. Find the cost of labor for 500 transmissions and the cost of materials for 500 transmissions.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #9723 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! a)add the two expressions \n" ); document.write( " = \n" ); document.write( "b)substitute x=500 into above expression \n" ); document.write( " \n" ); document.write( "=100 000+225 000+1350 \n" ); document.write( "=$326350 \n" ); document.write( "c)Labour= \n" ); document.write( " =$275550 \n" ); document.write( " Materials= \n" ); document.write( " =$50800. \n" ); document.write( "Or simply Total cost-Labour=Materials \n" ); document.write( "Pete \n" ); document.write( " |