document.write( "Question 20107: Solve the following problem. \r
\n" ); document.write( "\n" ); document.write( "Ace manufacturing has determined that the cost of labor for producing transmissions is 0.3x^2+400x+550 dollars, while the cost of materials is 0.1x^2+50x+800 dollars.\r
\n" ); document.write( "\n" ); document.write( "a. Write a polynomial that represents the total cost of materials and labor for producing x transmissions.
\n" ); document.write( "b. Evaluate the total cost polynomial for x=500.
\n" ); document.write( "c. Find the cost of labor for 500 transmissions and the cost of materials for 500 transmissions.\r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #9723 by pwac(253)\"\" \"About 
You can put this solution on YOUR website!
a)add the two expressions\"0.3x%5E2%2B400x%2B550\"+\"0.1x%5E2%2B50x%2B800\"
\n" ); document.write( " = \"0.4x%5E2%2B450x%2B1350\"
\n" ); document.write( "b)substitute x=500 into above expression
\n" ); document.write( "\"%280.4%28500%29%5E2%29%2B450%28500%29%2B1350\"
\n" ); document.write( "=100 000+225 000+1350
\n" ); document.write( "=$326350
\n" ); document.write( "c)Labour=\"%280.3%28500%29%5E2%29%2B400%28500%29%2B550\"
\n" ); document.write( " =$275550
\n" ); document.write( " Materials=\"%280.1%28500%29%5E2%29%2B50%28500%29%2B800\"
\n" ); document.write( " =$50800.
\n" ); document.write( "Or simply Total cost-Labour=Materials
\n" ); document.write( "Pete
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