document.write( "Question 132924: A spice mixture is 25% thyme. How many grams of thyme must be added to 12 g. of the misture to increase the thyme content to 40%? \n" ); document.write( "

Algebra.Com's Answer #97229 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of pure thyme that needs to be added\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure thyme in the 12 g mixture (0.25*12) plus the amount of pure thyme that is added (x) has to equal the amount of pure thyme in the final mixture (0.40(12+x)). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "0.25*12+x=0.40(x+12) get rid of parens and simplify\r
\n" ); document.write( "\n" ); document.write( "3+x=0.40x+4.8 subtract 3 and also 0.40x from each side\r
\n" ); document.write( "\n" ); document.write( "3-3+x-0.40x=0.40x-0.40x+4.8-3 collect like terms
\n" ); document.write( "0.60x=1.8 divide both sides by 0.60\r
\n" ); document.write( "\n" ); document.write( "x=3 gms--------------------amount of pure thyme needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.25*12+3=0.40(3+12)\r
\n" ); document.write( "\n" ); document.write( "3+3=0.40(15)
\n" ); document.write( "6=6\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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