document.write( "Question 133001: Write a quadratic equation in the variable \"x\" having the given numbers as solutions. Type the equation in standard, ax^2 + bx + c = 0.\r
\n" ); document.write( "\n" ); document.write( "Solution: 8, only solution\r
\n" ); document.write( "\n" ); document.write( "I am having trouble backing into the equation. Can someone help explain to me.\r
\n" ); document.write( "\n" ); document.write( "Thank you. \n" ); document.write( "

Algebra.Com's Answer #97218 by solver91311(24713) $\"\"$ $\"About$

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A quadratic equation $\"ax%5E2%2Bbx%2Bc=0\"$ has $\"p\"$ as a root if and only if $\"x-p\"$ is a factor of the polynomial $\"ax%5E2%2Bbx%2Bc\"$ . Since the Fundamental Theorem of Algebra tells us that a 2nd degree equation must have 2 roots, the root 8 must have a multiplicity of 2, in other words there are two roots and they are both 8. Therefore, the factors of the polynomial must be $\"%28x-8%29%28x-8%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Apply FOIL:
\n" ); document.write( " $\"x%5E2-16x%2B64\"$ \r
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\n" ); document.write( "\n" ); document.write( "And set the polynomial equal to zero:
\n" ); document.write( " $\"x%5E2-16x%2B64=0\"$ \n" ); document.write( "

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