document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=19998>Question 19998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It took 3 hours to row a boat 18 km against the current. The return trip with the current took 1.5 hours. Find the speed of the rowboat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #9721 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=9721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(t-18)=1.5(t+18)<BR>\n" );
document.write( "3t-54=1.5t+27<BR>\n" );
document.write( "3t=1.5t+81<BR>\n" );
document.write( "1.5t=81<BR>\n" );
document.write( "t=54<BR>\n" );
document.write( "Therefore, the speed of the boat in still water is 54km </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );