document.write( "Question 132985This question is from textbook intermediate algebra
\n" ); document.write( ": 5. Solve using the quadratic formula:
\n" ); document.write( "x^2 – 3x = 4x – 1
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #97182 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"x%5E2-3x=4x-1\" Start with the given equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x-4x%2B1=0\" Subtract 4x from both sides. Add 1 to both sides. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-7x%2B1=0\" Combine like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2-7%2Ax%2B1=0\" ( notice \"a=1\", \"b=-7\", and \"c=1\")\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%28--7+%2B-+sqrt%28+%28-7%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29\" Plug in a=1, b=-7, and c=1\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+sqrt%28+%28-7%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29\" Negate -7 to get 7\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+sqrt%28+49-4%2A1%2A1+%29%29%2F%282%2A1%29\" Square -7 to get 49 (note: remember when you square -7, you must square the negative as well. This is because \"%28-7%29%5E2=-7%2A-7=49\".)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+sqrt%28+49%2B-4+%29%29%2F%282%2A1%29\" Multiply \"-4%2A1%2A1\" to get \"-4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+sqrt%28+45+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+3%2Asqrt%285%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B-+3%2Asqrt%285%29%29%2F2\" Multiply 2 and 1 to get 2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%287+%2B+3%2Asqrt%285%29%29%2F2\" or \"x+=+%287+-+3%2Asqrt%285%29%29%2F2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=6.85410196624968\" or \"x=0.145898033750315\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=6.85410196624968\" or \"x=0.145898033750315\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2-7%2Ax%2B1\", we get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=6.85410196624968\" and \"x=0.145898033750315\".So this verifies our answer\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );