document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132949>Question 132949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 24mph to visit a nearby town.  The cyclist averaged 18mph on the return trip.  If the round trip took 4.9 hours find the distance to the nearby town. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97174 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D/24+D/18=4.9<BR>\n" );
document.write( "(18D+24D)/24*18=4.9<BR>\n" );
document.write( "42D/432=4.9<BR>\n" );
document.write( "42D=432*4.9<BR>\n" );
document.write( "42D=2116.8<BR>\n" );
document.write( "D=2116.8/42<BR>\n" );
document.write( "D=50.4 MILES IS THE DISTANCE TO THE NEARBY TOWN.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "50.4/24+50.4/18=4.9<BR>\n" );
document.write( "2.1+2.8=4.9<BR>\n" );
document.write( "4.9=4.9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );