document.write( "Question 132965This question is from textbook
\n" ); document.write( ": 1-i/1+i*2+i/1+i \n" ); document.write( "

Algebra.Com's Answer #97167 by vleith(2983) $\"\"$ $\"About$

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$\"1-i%2F1%2Bi%2A2%2Bi%2F1%2Bi\"$ \r
\n" ); document.write( "\n" ); document.write( "i/1 = i
\n" ); document.write( "-i/i = -i\r
\n" ); document.write( "\n" ); document.write( "Thus we get $\"1+-i+%2Bi%2A2+%2Bi+%2B+i\"$ \r
\n" ); document.write( "\n" ); document.write( "Yielding $\"1+-i+%2B2i+%2B+i\"$ \r
\n" ); document.write( "\n" ); document.write( "Collecting like term yields $\"1+%2B+2i\"$ \r
\n" ); document.write( "\n" ); document.write( "If, by chance you meant to write $\"i%5E2\"$ instead of $\"i%2A2\"$ then just do the same steps but substitute -1 for $\"i%5E2\"$ \n" ); document.write( "

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