document.write( "Question 132885: i need help with this word problem can anyone help me?\r
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document.write( "Soybean meal is 16% protein, COrnmeal is 8% portein. Howmany pounds of each should be mixed together in order to get a 320lb mixture that is 14% proetien?
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document.write( "Cornmeal__________pounds
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document.write( "Soybean____________pounds \n" );
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Algebra.Com's Answer #97145 by ptaylor(2198) You can put this solution on YOUR website! Let x=amount of soybean meal needed \n" ); document.write( "Then 320-x=amount of cornmeal needed\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure protein in the soybean meal (0.16x) plus the amount of pure protein in the cornmeal (0.08(320-x)) has to equal the amount of pure protein in the final mixture (0.14*320). So our equation to solve:\r \n" ); document.write( "\n" ); document.write( "0.16x+0.08(320-x)=0.14*320 simplify\r \n" ); document.write( "\n" ); document.write( "0.16x+25.6-0.08x=44.8 subtract 25.6 from each side\r \n" ); document.write( "\n" ); document.write( "0.16x+25.6-25.6-0.08x=44.8-25.6 collect like terms \n" ); document.write( "0.08x=19.2 divide both sides by 0.08 \n" ); document.write( "x=240 lb----------------------amount of soybean meal needed\r \n" ); document.write( "\n" ); document.write( "320-x=320-240=80 lb-----------------amount of cornmeal needed\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "240*0.16+80*0.08=0.14*320\r \n" ); document.write( "\n" ); document.write( "38.4+6.4=44.8 \n" ); document.write( "44.8=44.8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |