document.write( "Question 132939: Please help me solve this:\r
\n" ); document.write( "\n" ); document.write( "1/a+1/b=c for b
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Algebra.Com's Answer #97135 by josmiceli(19441)\"\" \"About 
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\"1%2Fa+%2B+1%2Fb+=+c\"
\n" ); document.write( "multiply both sides by \"b\"
\n" ); document.write( "\"b%2Fa+%2B+1+=+bc\"
\n" ); document.write( "Subtract \"bc\" from both sides
\n" ); document.write( "\"b%2Fa+-+bc+%2B+1+=+0\"
\n" ); document.write( "Subtract \"1\" from both sides
\n" ); document.write( "\"b%2Fa+-+bc+=+-1\"
\n" ); document.write( "Factor out \"b\" from left side
\n" ); document.write( "\"b%281%2Fa+-+c%29+=+-1\"
\n" ); document.write( "Divide both sides by \"1%2Fa+-+c\"
\n" ); document.write( "\"b+=+%28-1%29+%2F+%281%2Fa+-+c%29\"
\n" ); document.write( "To simplify the right side, multiply
\n" ); document.write( "the right side by \"%28-a%29%2F%28-a%29\", which is \"1\",
\n" ); document.write( "so nothing is really changed
\n" ); document.write( "\"b+=+a+%2F+%28ac+-+1%29\" answer
\n" ); document.write( "check answer:
\n" ); document.write( "\"1%2Fa+%2B+1%2Fb+=+c\"
\n" ); document.write( "What is \"1%2Fb\"?
\n" ); document.write( "\"1%2Fb+=+%28ac+-+1%29+%2F+a\" (from the answer)
\n" ); document.write( "\"1%2Fa+%2B+%28ac-1%29%2Fa+=+c\"
\n" ); document.write( "Multiply both sides by \"a\"
\n" ); document.write( "\"1+%2B+ac+-+1+=+ac\"
\n" ); document.write( "\"ac+=+ac\"
\n" ); document.write( "OK
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