document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132889>Question 132889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a=x(^1/2)- 4x(^-1/2). What is the value of 1/a^-2??? I think the answer is x^2-8x+16/x , can someone please confirm ???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97132 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=x(^1/2)- 4x^(-1/2) I assume that this is the problem.<BR>\n" );
document.write( "4x^(-1/2)=4/sqrt(x) since only x is taken to the -1/2 power.<BR>\n" );
document.write( "1/a^-2=a^2<BR>\n" );
document.write( "a^2=(sqrt(x)-4/sqrt(x))^2<BR>\n" );
document.write( "=x-8+ 16/x <BR>\n" );
document.write( "You were almost correct the -8 doesn't have an x after it and the x isn't squared.<BR>\n" );
document.write( "sqrt(x)* -4/sqrt(x)=-4sqrt(x)/sqrt(x)=-4<BR>\n" );
document.write( "sqrt(x)^2=x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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