document.write( "Question 132922: Find the two numbers whose sum is 45 and such that one is 4 times as large as the other. \n" ); document.write( "
Algebra.Com's Answer #97125 by jim_thompson5910(35256)\"\" \"About 
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\"two numbers whose sum is 45\"---> \"x%2By=45\"\r
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\n" ); document.write( "\n" ); document.write( "\"one is 4 times as large\"----> \"y=4x\"\r
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\n" ); document.write( "\n" ); document.write( "Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=45\"
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\n" ); document.write( "\n" ); document.write( "\"x%2B4x=45\" Plug in \"y=4x\" into the first equation. In other words, replace each \"y\" with \"4x\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"5x=45\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2845%29%2F%285%29\" Divide both sides by 5 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=9\" Divide. So our first number is 9\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=9\", we can plug this into \"y=4x\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=4%289%29\" Substitute \"9\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=36\" Simplify. So our second number is 36\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=9\" and \"y=36\" which means that our two numbers are 9 and 36\r
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