document.write( "Question 132875This question is from textbook
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document.write( ": A salesperson purchased an automobile that was advertised as averaging 25 mi/gal in the city and 40 mi/gal on the highway. A recent sales trip that covered 1800 miles required 51 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?\r
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Algebra.Com's Answer #97095 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "1800 total miles \n" ); document.write( "51 gallons \n" ); document.write( "25 miles per gallon city \n" ); document.write( "40 miles per gallon highway\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The total distance is the sum of the mileage of city and highway. \n" ); document.write( "Let x be the number of gallons used for city driving. If so, then 51-x is the number of gallons used for highway. \r \n" ); document.write( "\n" ); document.write( "Now setup an equation for the total mileage driven\r \n" ); document.write( "\n" ); document.write( "Thus : \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yielding 400\r \n" ); document.write( "\n" ); document.write( "Check your answer using highway milage to ensure the total is correct. \n" ); document.write( "51-16 = 35 \n" ); document.write( "35 * 40 = 1400\r \n" ); document.write( "\n" ); document.write( "total is 1400 + 400 = 1800!! \n" ); document.write( " |