document.write( "Question 132815This question is from textbook
\n" ); document.write( ": the other problems I submitted are also in the same chapter of this book. thank you so much!\r
\n" ); document.write( "\n" ); document.write( "the frame of a picture is 28 cm by 32 cm outside and is of uniform width. What is the width of the frame if 192 cm^2 of the picture shows? \n" ); document.write( "
Algebra.Com's Answer #97079 by nycsharkman(136)\"\" \"About 
You can put this solution on YOUR website!
The picture is a rectangle formed by removing a constant from both dimensions of the outer frame 28 x 32.\r
\n" ); document.write( "\n" ); document.write( "(28 - c)(32 - c) = 192
\n" ); document.write( "896 - 60c + c^2 = 192
\n" ); document.write( "c^2 - 60c + 704 = 0
\n" ); document.write( "(c - 44)(c - 16) = 0\r
\n" ); document.write( "\n" ); document.write( "so c = 44 or c = 16.\r
\n" ); document.write( "\n" ); document.write( "Now c represents twice the frame width, because the frame removes area from both sides (and from top AND bottom) of the picture. 44 cm is bigger than the picture, so it's not an answer. If c = 16, then the picture is 12cm by 16cm = 192 cm^2, which checks.\r
\n" ); document.write( "\n" ); document.write( "Therefore the frame is 8 cm wide.
\n" ); document.write( " \n" ); document.write( "
\n" );