document.write( "Question 132828: Some students planned for a get-together. The budget for food was $500. Five of the students failed to come because of the distance and therefore the cost of food for each member increased by $5. How many students attended the get-together?
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Algebra.Com's Answer #97068 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 500/X=500/(X-5)-5 \n" ); document.write( "500/X-500/(X-5)=-5 \n" ); document.write( "(500(X-5)+X)/X(X-5)=-5 \n" ); document.write( "(500X-2500-500X)/(X^2+5X)=-5 CROSS MULTIPLY. \n" ); document.write( "-5(X^2+5X)=-2500 \n" ); document.write( "-5X^2+25X+2500=0 \n" ); document.write( "-5(X^2-5X-500=0 \n" ); document.write( "-5(X-25)(X+20)=0 \n" ); document.write( "X-25=0 \n" ); document.write( "X=25 NUMBER OF STUDENTS ORIGINALLY PLANNED TO ATTEND. \n" ); document.write( "PROOF: \n" ); document.write( "500/25=500/(25-5)-5 \n" ); document.write( "20=(500/20)-5 \n" ); document.write( "25=25-5 \n" ); document.write( "20=20\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |