document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132831>Question 132831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rita rows 12 km upstream and 12 km downstream in 3 hours. The speed of her boat in still water is 9 km/hr. Find the speed of the stream </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #97063 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=97063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12/(9-X)+12/(9+X)=3<BR>\n" );
document.write( "[12(9+X)+12(9-X)]/(9+X)(9-X)=3<BR>\n" );
document.write( "[108(12X+108-12X]/(81-X^2)=3<BR>\n" );
document.write( "216/(81-X^2)=3 NOW CROSS MULTIPLY<BR>\n" );
document.write( "3(81-X^2)=216<BR>\n" );
document.write( "243-3X^2-216=0<BR>\n" );
document.write( "-3X^2+27=0<BR>\n" );
document.write( "-3(X^2-9)=0<BR>\n" );
document.write( "-3(X+3)(X-3)=0<BR>\n" );
document.write( "X-3=0<BR>\n" );
document.write( "X=3 KMH IS THE SPEED OF THE CURRENT.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12/(9-3)+12/(9+3)=3<BR>\n" );
document.write( "12/6+12/12=3<BR>\n" );
document.write( "2+1=3<BR>\n" );
document.write( "3=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );