document.write( "Question 132806: The speed of a passenger train is 14 mph faster than the speed of a feight train. The passenger train travels 400 mi in the same time that it takes the freight train to travel 330 mi. Find the speed of each train. \n" ); document.write( "
Algebra.Com's Answer #97050 by solver91311(24713)\"\" \"About 
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Remember that distance equals rate times time, or \"d=rt\".\r
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\n" ); document.write( "\n" ); document.write( "If the rate of the freight train is r, then the rate of the passenger train is r + 14.\r
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\n" ); document.write( "\n" ); document.write( "We can rewrite \"d=rt\" as \"t=d%2Fr\".\r
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\n" ); document.write( "\n" ); document.write( "For the freight train: \"t=330%2Fr\", and for the passenger train: \"t=400%2F%28r%2B14%29\". We know that the times are equal because the problem says \"same time\", so we can say:\r
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\n" ); document.write( "\n" ); document.write( "\"400%2F%28r-14%29=330%2Fr\"\r
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\n" ); document.write( "\n" ); document.write( "To solve a proportion, first cross-multiply:
\n" ); document.write( "\"400r=330%28r%2B14%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"400r=330r%2B4620\"\r
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\n" ); document.write( "\n" ); document.write( "\"400r-330r=4620\"\r
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\n" ); document.write( "\n" ); document.write( "\"70r=4620\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=66\"\r
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\n" ); document.write( "\n" ); document.write( "The speed of the freight train is 66 mph, and the speed of the passenger train is 66 + 14 = 80 mph.\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"400%2F80=5\"hours\r
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\n" ); document.write( "\n" ); document.write( "\"330%2F66=5\"hours\r
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\n" ); document.write( "\n" ); document.write( "The times are the same, so the answer checks.\r
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