document.write( "Question 132806: The speed of a passenger train is 14 mph faster than the speed of a feight train. The passenger train travels 400 mi in the same time that it takes the freight train to travel 330 mi. Find the speed of each train. \n" ); document.write( "
| Algebra.Com's Answer #97050 by solver91311(24713)     You can put this solution on YOUR website! Remember that distance equals rate times time, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the rate of the freight train is r, then the rate of the passenger train is r + 14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We can rewrite \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the freight train: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To solve a proportion, first cross-multiply: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The speed of the freight train is 66 mph, and the speed of the passenger train is 66 + 14 = 80 mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The times are the same, so the answer checks.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |