document.write( "Question 132740This question is from textbook Algebra & Trigono,etry
\n" ); document.write( ": Find the x and y intercepts of the equation.\r
\n" ); document.write( "\n" ); document.write( "x^2 + 8x +12 = 0
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Algebra.Com's Answer #97033 by solver91311(24713)\"\" \"About 
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The equation, as you presented it, doesn't have any \"intercepts.\" This quadratic equation has two solutions or roots that would be the x-intercepts of the function \"y+=+f%28x%29+=x%5E2+%2B+8x+%2B12\". This function would also have a y-intercept at (0,f(0)).\r
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\n" ); document.write( "\n" ); document.write( "If you meant to ask for the x-intercepts of \"y+=+f%28x%29+=x%5E2+%2B+8x+%2B12\", then the method to find them consists of setting the function equal to 0, resulting in the equation you provided, and then solving for x.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+8x+%2B12+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "6 * 2 = 12 and 6 + 2 = 8, so:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%28x%2B2%29=0\", therefore x = -6 or x = -2, and the x-intercepts of \"y+=+f%28x%29+=x%5E2+%2B+8x+%2B12\" are the two points denoted by the ordered pairs (-6,0) and (-2,0).\r
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\n" ); document.write( "\n" ); document.write( "As previously discussed the y-intercept of \"y+=+f%28x%29+=x%5E2+%2B+8x+%2B12\" is at the point (0,f(0)). \"f%280%29+=0%5E2+%2B+8%280%29+%2B12=12\", so the y-intercept is at the point (0,12).
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