document.write( "Question 132749: Which function has a domain {xsuch thatx is less than 2, x is R}?
\n" ); document.write( "a) -1/4(y-2)=(x+5)^2
\n" ); document.write( "b) y=3(4)(^-(x-2)) +2
\n" ); document.write( "c) y=log(4-2x)
\n" ); document.write( "d) y=log base1/2 (x-2)
\n" ); document.write( "I think the answer is (B)?????????
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Algebra.Com's Answer #97020 by solver91311(24713)\"\" \"About 
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Choice a: rewrite to \"y=-4%28x%2B5%29%5E2%2B2\". This function is defined for all real x, so x < 2 does not make this function undefined. Incorrect.\r
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\n" ); document.write( "\n" ); document.write( "Choice b: x < 2 ensures that the exponent on 4 is positive, but there is nothing wrong with the exponent on 4 being negative or zero, so again, the domain of this function is all reals. Incorrect.\r
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\n" ); document.write( "\n" ); document.write( "Choice c: the domain of log(x) is all positive reals. In order for 4 - 2x to be positive, x must be less than 2. This is the correct function for the given domain.\r
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\n" ); document.write( "\n" ); document.write( "Choice d: again, the domain of log(x) is all positive reals, but in the choice d function, a value for x < 2 would make x - 2 be less than zero. The domain here is {x|x is Real, x > 2}. Incorrect.
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