document.write( "Question 132751: With Current, a motorboat travels 60 mi in 3 h. Against the current, it takes 2h longer to travel 60 mi. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #97013 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! Rate of the boat in still water: \n" ); document.write( "Rate of the current: \n" ); document.write( "Then: \n" ); document.write( "Rate of the boat with the current: \n" ); document.write( "Rate of the boat against the current: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But we know that \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the two equations term by term to eliminate \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "16 + 4 = 20 mph times 3 hours = 60 miles \n" ); document.write( "16 - 4 = 12 mph times (3 + 2) hours = 60 miles \n" ); document.write( "Answer checks. \n" ); document.write( " |