document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=132699>Question 132699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rationalize the denominator:<BR>\n" );
document.write( "          2 divided by &#8730;[3] + &#8730;[2]<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #96989 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=96989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rationalize the denominator:<BR>\n" );
document.write( "2 divided by &#8730;[3] + &#8730;[2]<BR>\n" );
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document.write( "2/[sqrt(3) + sqrt(2)]\r<BR>\n" );
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document.write( "Multiply numerator and denominator by [sqrt(3)-sqrt(2)] to get:\r<BR>\n" );
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document.write( "= 2(sqrt(3)-sqrt(2))/(3-2)\r<BR>\n" );
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document.write( "= 2sqrt(3)-2sqrt(2)\r<BR>\n" );
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document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );