document.write( "Question 132663: An instrument store gives a 10% discount to all students off the original cost of an instrument. During a back to school sale an additional 15% is taken off the discounted price. a student purchases a flute for $306. \r
\n" ); document.write( "\n" ); document.write( " I need to find the original price,but i don't know where to start, please help me thanks.
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Algebra.Com's Answer #96986 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Call the original price \"p\"
\n" ); document.write( "With the 1st discount, the instrument sells for \"p+-+.1p+=+.9p\"
\n" ); document.write( "After the 2nd discount, it sells for \".9p+-+.15%28.9p%29\"
\n" ); document.write( "\".9p+-+.15%28.9p%29+=+.9p+-+.135p\"
\n" ); document.write( "\".9p+-+.135p+=+.765p\"
\n" ); document.write( "\".765p+=+306\"
\n" ); document.write( "\"p+=+400\"
\n" ); document.write( "The original price of the flute was $400
\n" ); document.write( "check:
\n" ); document.write( "\"p+-+.1p+=+.9p\"
\n" ); document.write( "\"400+-+.1%2A400+=+360\"
\n" ); document.write( "\".9p+-+.135p+=+.765p\"
\n" ); document.write( "\"360+-+.135%2A400+=+.765p\"
\n" ); document.write( "\"360+-+54+=+306\"
\n" ); document.write( "\"306+=+306\"
\n" ); document.write( "OK
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