document.write( "Question 132642: \r
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\n" ); document.write( "\n" ); document.write( "x+y/7 for x=36 and y=13\r
\n" ); document.write( "\n" ); document.write( "x+y/7=\r
\n" ); document.write( "\n" ); document.write( "Help would this be 7?
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Algebra.Com's Answer #96966 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
X+Y//7
\n" ); document.write( "36+13/7
\n" ); document.write( "(36*7+13)/7
\n" ); document.write( "(252+13)/7
\n" ); document.write( "265/7 OR 37.857142 ANSWER.
\n" ); document.write( "-------------------------------------------
\n" ); document.write( "IF YOU MEAN (X+Y)/7 THEN:
\n" ); document.write( "(36+13)/7
\n" ); document.write( "49/7=7 ANSWER.
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