document.write( "Question 132649: A hot cup of coffee is left outside where it cools exponentially. The temperature, T, of the coffee in degrees Celsius after t minutes is modeled by the function T=66(b)^(x/2)+17. The temperature of the coffee after 9 minutes is 56 degrees Celsius. What is the rate of cooling?
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document.write( "I think the answer is 3% every two minutes???? \n" );
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Algebra.Com's Answer #96943 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A hot cup of coffee is left outside where it cools exponentially. The temperature, T, of the coffee in degrees Celsius after t minutes is modeled by the function T=66(b)^(x/2)+17. The temperature of the coffee after 9 minutes is 56 degrees Celsius. What is the rate of cooling? \n" ); document.write( "I think the answer is 3% every two minutes???? \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "T=66(b)^(x/2)+17 \n" ); document.write( "--------------- \n" ); document.write( "56 = 66*b^(9/2)+17 \n" ); document.write( "39 = 66*b^(9/2) \n" ); document.write( "13/22 = b^(9/2) \n" ); document.write( "Raise both sides to the (2/9) to solve for b: \n" ); document.write( "b = 0.889666.... \n" ); document.write( "------------------------- \n" ); document.write( "Formula: \n" ); document.write( "T(x) = 66*(0.889666)^(x/2) + 17 \n" ); document.write( "T(0) = 66*(1)+17 \n" ); document.write( "T(0) = 83 degrees \n" ); document.write( "T(9) = 56 degrees \n" ); document.write( "--------------------- \n" ); document.write( "Average = (56-83)/9 = -3 degrees per minute \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |